Framebuffer的16位色,RBG是怎样排列的?
Framebuffer的16位色,RBG是怎样排列的? 一般都是 5-6-5 r,b 都是5位. G是6位 #include <stdio.h>#include <stdlib.h>
#include <fcntl.h>
#include <unistd.h>
#include <string.h>
#include <sys/ioctl.h>
#include <sys/mman.h>
#include <asm/page.h>
#include <linux/fb.h>
int fb;
struct fb_var_screeninfo vinfo;
struct fb_fix_screeninfo finfo;
typedef struct {
unsigned char r;
unsigned char g;
unsigned char b;
}rgb_t;
unsigned long screen_size;
unsigned char * lpScreenMem;
int main(int argc, char ** argv)
{
int i, j;
rgb_t rgb;
fb = open("/dev/fb0", O_RDWR);
if (fb < 0) {
fprintf(stderr, "open /dev/fb0 error!\n");
return -1;
}
if (ioctl(fb, FBIOGET_VSCREENINFO, &vinfo)) {
fprintf(stderr, "error get var screeninfo!\n");
return -1;
}
printf("%dx%d %dbpp\n", vinfo.xres, vinfo.yres, vinfo.bits_per_pixel);
screen_size = vinfo.xres * vinfo.yres * (vinfo.bits_per_pixel / 8);
lpScreenMem = (unsigned char *)mmap(0, screen_size, PROT_READ | PROT_WRITE, MAP_SHARED, fb, 0);
if (lpScreenMem == -1) {
return -1;
}
rgb.r = 0xff;
rgb.g = 0x00;
rgb.b = 0x00;
for (i = 0;i < 100;i ++) {
//draw_point(0, i, rgb);
for (j = 0;j < 100;j ++) {
draw_point(i, j, rgb);
}
}
close(fb);
}
void draw_point(int x, int y, rgb_t rgb)
{
unsigned short * lpMem = (unsigned short *)(lpScreenMem + (x + y * vinfo.xres * 2));
*lpMem = (unsigned short)((((unsigned short)rgb.r & 0x1f) << 11) + (((unsigned short)rgb.g & 0x3f) << 5) + (unsigned short)rgb.b);
}
我的颜色老是设置不对,你看看那里有错,先谢谢了! 我知道是那里错了,谢谢你了!
把lpScreenMem + (x + y * vinfo.xres * 2)改成
lpScreenMem + (x + y * vinfo.xres) * 2就对了!
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