client 和server可以调换吗？高手快帮忙
一个消息的创建程序是这样的：那么为何程序中server在前，而client 在后；如果在输程序中将二者交换时，为何结果如此奇怪？？？
交替出现是为什么？
#include <unistd.h>
#include <signal.h>
#include <stdio.h>
int pid1=0,pid2=0;
int EndFlag=0;
void IntDelete()
{
kill(pid1,16);
kill(pid2,17);
EndFlag=1;
}
void Int1()
{
printf("child process 2 is killed! by parent \n");
exit(0);
}
void Int2()
{
printf("child process 2 is killed !by parent \n");
exit(0);
}
main()
{
int exitpid;
signal(SIGINT,SIG_IGN);
signal(SIGQUIT,SIG_IGN);
while ((pid1=fork())==-1);
if (pid1==0)
{
signal(SIGUSR1,Int1);
signal(SIGINT,SIG_IGN);
pause();
exit(0);
}
else
{
while((pid2=fork())==-1);
if (pid2==0)
{
signal(SIGUSR1,Int2);
signal(SIGINT,SIG_IGN);
pause();
exit(0);
}
else
{
signal(SIGINT,IntDelete);
waitpid(-1,&exitpid,0);
printf("parent process is killed \n");
exit(0);
}
}
} 注意他们的通信机制！！！ u have not describ ur problem clearly, but the sequence of process execution is not depend on the sequence u type in. maybe i am wrong, sorry not to help u
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