截取一行中的部份字串
Powered by <a href="http://www.phpbb.com/" target="_phpbb" class="copyright">phpBB</a> 2.0.3 &copy; 2001 phpBB Group<br /><br>請問如何截取這行中 http://www.phpbb.com/ 這個字串? 謝謝! grep -o 'http://[a-z.]*/'
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